Hello gentelmen,
can anybody guide or point me how to compile mysql (4.0) with specific
zlib library?
I've precompiled zlib which came with OS (FreeBSD 4.5) in /usr/lib:
libz.a
libz.so
libz.so.1
libz.so.1.1.3
libz.so.2
and have installed myself libz 1.1.4 to /opt/zlib (with usual structure
/opt/zlib/include, /opt/zlib/lib). Added path to $ldconfig_paths FreeBSD's
rc.conf variable, saw this library with
# ldconfig -r
...
78:-lmm.13 => /opt/mm/lib/libmm.so.13
79:-lz.1 => /opt/zlib/lib/libz.so.1
80:-lcrypto.0 => /opt/openssl/lib/libcrypto.so.0
81:-lssl.0 => /opt/openssl/lib/libssl.so.0
So now I want to compile mysql with this library, but it always compiled
to /usr/lib
Even I've used various ways like:
--with-named-z-libs=/opt/zlib
and
--with-named-z-libs=/opt/zlib/lib
and other variants like pointing:
LDFLAGS="-L/opt/zlib/lib -R/opt/zlib/lib"
LIBS="-L/opt/zlib/lib" (after took a look to configure script)
CFLAGS="-L/opt/zlib/lib"
an so on it or not compiled with zlib or still used from /usr/lib
# ldd mysqld
mysqld:
libssl.so.0.9.7 => /opt/openssl/lib/libssl.so.0.9.7 (0x2834b000)
libcrypto.so.0.9.7 => /opt/openssl/lib/libcrypto.so.0.9.7
(0x28379000)
libz.so.2 => /usr/lib/libz.so.2 (0x28465000)
libcrypt.so.2 => /usr/lib/libcrypt.so.2 (0x28472000)
libstdc++.so.3 => /usr/lib/libstdc++.so.3 (0x2848b000)
libm.so.2 => /usr/lib/libm.so.2 (0x284d0000)
libc_r.so.4 => /usr/lib/libc_r.so.4 (0x284ec000)
libc.so.4 => /usr/lib/libc.so.4 (0x285a1000)
# ldd mysql
mysql:
libncurses.so.5 => /usr/lib/libncurses.so.5 (0x28085000)
libmysqlclient.so.12 => /opt/mysql/lib/mysql/libmysqlclient.so.12
(0x280c7000)
libz.so.2 => /usr/lib/libz.so.2 (0x280eb000)
libcrypt.so.2 => /usr/lib/libcrypt.so.2 (0x280f8000)
libssl.so.0.9.7 => /opt/openssl/lib/libssl.so.0.9.7 (0x28111000)
libcrypto.so.0.9.7 => /opt/openssl/lib/libcrypto.so.0.9.7
(0x2813f000)
libstdc++.so.3 => /usr/lib/libstdc++.so.3 (0x2822b000)
libm.so.2 => /usr/lib/libm.so.2 (0x28270000)
libc.so.4 => /usr/lib/libc.so.4 (0x2828c000)
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