Rogers, Dennis wrote:
Good afternoon,
How can I take the 3 results below add them together then divide by
131.77?
Can it all be done in one SQL statement?
Thanks in advance.
mysql> describe ads;
+-----------+---------------+------+-----+------------+----------------+
| Field | Type | Null | Key | Default | Extra
|
+-----------+---------------+------+-----+------------+----------------+
| adID | int(11) | | PRI | NULL |
auto_increment |
| page | int(11) | | | 0 |
|
| adnum | varchar(20) | | | |
|
| date | date | | | 0000-00-00 |
|
| depth | decimal(3,2) | YES | | 0.00 |
|
| timestamp | timestamp(14) | YES | | NULL |
|
| col | int(11) | YES | | 0 |
|
| acc | varchar(50) | | | |
|
| editionID | int(11) | | | 0 |
|
+-----------+---------------+------+-----+------------+----------------+
9 rows in set (0.00 sec)
mysql> SELECT ((ads.col * 1.91) * ads.depth) FROM ads Where date =
'2004-02-26' AND editionID = '13' AND ads.page = '16';
+---------------------------------+
| ((ads.col * 1.91) * ads.depth) |
+---------------------------------+
| 7.64 |
| 34.38 |
| 7.64 |
+---------------------------------+
3 rows in set (0.01 sec)
SELECT SUM((ads.col * 1.91) * ads.depth)/131.77 FROM ads Where date =
'2004-02-26' AND editionID = '13' AND ads.page = '16';
--
Sasha Pachev
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