WHERE (nickname = '$nickname') and (password = '$password')", $connection);

remember to place quotes around the value

nickname = $nickname wont work but
nickname = '$nickname'  will do

Hope that helps

Nitin


----- Original Message ----- 
From: "electroteque" <[EMAIL PROTECTED]>
To: "Togochog Enhebatu" <[EMAIL PROTECTED]>; <[EMAIL PROTECTED]>
Sent: Saturday, February 28, 2004 2:54 AM
Subject: RE: help on PHP code


> well dude u never showed what the parser returned, i am pretty sure u need
> curly brackets if u are including more than one line in an if statement
>
> -----Original Message-----
> From: Togochog Enhebatu [mailto:[EMAIL PROTECTED]
> Sent: Saturday, February 28, 2004 2:53 PM
> To: [EMAIL PROTECTED]
> Subject: help on PHP code
>
>
> hi,
>
> Can any one help find the bug of the following code for me? I am new in
> MySQL and PHP, and trying to varify the user ID and password.
>
> help is appreciated.
>
> batu,
>
> ************
>
>
> <!DOCTYPE HTML PUBLIC
>     "-//W3C//DTD HTML 4.0 Transitional//EN"
>     "http://www.w3.org/TR/html4/loose.dtd";>
> <html>
> <head><title>Customer Details</title></head>
> <body bgcolor="green">
> <h1>Customer Details</h1>
>
>
> <?php
>
> $nickname = $HTTP_POST_VARS['nickname'];
> if(empty($nickname))
>         echo '<br>nickname field should not be blank.';
>
> $password = $HTTP_POST_VARS['password'];
> if(empty($password))
>         echo '<br>password field should not be blank.';
> ?>
>
> <?php
>
> $connection=mysql_connect("localhost","csc3223","abdasa");
>
> mysql_select_db("csc3223",$connection);
>
>
> $result=mysql_query("SELECT nickname,password,status FROM Exam_Provider
> WHERE (n
> ickname = $nickname) and (password = $password)", $connection);
>
>
> while ($row = mysql_fetch_array($result))
>
>      {
>         echo "you have not been approved yet";
>      }
>
> mysql_close($connection);
>
> ?>
>
>
> <a href="form.html"><br><br>Return to the customer form</a>
> </body>
> </html>
>
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