It is interesting to see the various solutions being proposed. Though one item missing is the inclusion of a 1 year old child. It is likely this will be the telling point since it provides one of the possible limiting criteria not mentioned. Most buildings have an even number of windows. So one of the few ways to get an even sum is to utilize the 1 with respect to the other pair of possible ages. What I see as likely candidates are
(1, 3, 12) and (1, 4, 9). Brad Eacker ([EMAIL PROTECTED])
The above two do not work (as well as a good number of other possibilities) - they are the *only* way to produce their sum under the conditions of the problem, which means that the information about the existence of the eldest would not have been required to figure out the ages.
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