Thank you Chris for that answer.  I did not know if it was a mysql problem
or php problem.


Again I apologize (especially to Mike Johsnon) for the multiple request.  I
was getting a return error on the list and I thought it was a configuration
error on my part.  I did not mean to upset anyone.  Thank you again for the
answer and I will try to have better netiquette in the future.
----- Original Message ----- 
From: "Chris" <[EMAIL PROTECTED]>
To: "Mysql" <[EMAIL PROTECTED]>
Sent: Wednesday, April 21, 2004 4:54 PM
Subject: RE: re-using a results set


> This is a PHP question, not MySQL.
>
> http://www.php.net/mysql_data_seek
>
>
> -----Original Message-----
> From: Scott Swaim [mailto:[EMAIL PROTECTED]
> Sent: Wednesday, April 21, 2004 2:47 PM
> To: Mysql
> Subject: re-using a results set
>
>
> I have a form that does the following
>
>                 <? while ($speaker = mysql_fetch_object($qid_speaker)) {
?>
>                                 <option value="<? pv($speaker->first_name)
> ?> <? pv($speaker->last_name) ?>">
>                                         <? pv($speaker->first_name) ?> <?
> pv($speaker->last_name) ?>
>                 <? } ?>
>                         </select>
>
> $qid_speaker = db_query("SELECT first_name, last_name FROM people WHERE
> speaker = 'Y' ORDER BY last_name");
>
>
> I am using this in a form select drop down box.
>
> What I need to do is reuse this results set in another drop down box.  but
I
> can not figure out how to do this.
> If I use the mysql_free-result($qid_speaker) and then try to do the query
> again I get a mysql_fetch_object(): 12 is not a valid MYSQL result
resource.
>
>
> TIA
>
> Scott Swaim
> Quality Corps, Inc.
>
>
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