Jigal van Hemert wrote:
I don#t understand why subquery on my MySQL 4.0.18-Mas does not valid. select * from salesreport where custid in (select custid from appointment where done='N');
Simple reason: v. 4.0.18 does not support subqueries yet. Use 4.1 or later.
Regards, Jigal.
Or, rewrite the query as a join.
SELECT * FROM salesreport s, appointment a WHERE s.custid = a.custid AND a.done = 'N';
See <http://dev.mysql.com/doc/mysql/en/Rewriting_subqueries.html>.
Michael
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