Thank you very much Lachlan and SpamVortex! I appreciate the help! Jonathan >>>[EMAIL PROTECTED] 07/07 6:59 pm >>> You can do it one of two ways.. Either you can do a "self join" like the following: select t1.userid from answers t1, answers t2 where t1.qid = 5 and lower(t1.answer)='student' and t2.qid = 6 and lower(t2.answer) like 'edu%' and t1.userid = t2.userid or you can use a union (available in 4.0.0 or greater) select userid from answers where qid = 5 and lower(answer) = 'student' UNION select userid from answers where qid = 6 and lower(answer) like 'edu%' union automatically does a distinct so you will get one row back for each user that answered that they are education students. --- Jonathan Duncan <[EMAIL PROTECTED]> wrote: >I am trying to figure out what my select statement >should be to combine >both of these into one: > >SELECT userid FROM Answers WHERE answer like >"Education%"; >SELECT userid FROM Answers WHERE answer="Student"; > >Table Answers looks like: >-id int >-userid int >-answer text > >for each row there would be something like: >+-----+--------+----------+ >| qid | userid | answer | >+-----+--------+----------+ >| 5 | 3000 | Student | >+-----+--------+----------+ > >There are often multiple asnwers for each question. > >I want to select the userid's from the table where >people answered >"Student" in question 5 and "Education" in question >6. > >I am using MySQL 4.08 so I can't do the subquery >thing. > >Thanks, >Jonathan Duncan > >-- >MySQL General Mailing List >For list archives: http://lists.mysql.com/mysql >To unsubscribe: > http://lists.mysql.com/[EMAIL PROTECTED] > > -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe: http://lists.mysql.com/[EMAIL PROTECTED]
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