Cong wrote:
> ...
> public class ExternalProgram
> {
> public static int ExecuteProgram(string program, string arguments)
> {
> Process process = new Process();
> process.StartInfo.FileName = program;
> process.StartInfo.Arguments = arguments;
> process.StartInfo.UseShellExecute = false;
> process.StartInfo.RedirectStandardOutput = true;
> process.StartInfo.RedirectStandardError = true;
> process.StartInfo.CreateNoWindow = true;
> process.Start();
>
> process.WaitForExit();
I don't see how this can work at all. If you look at the documentation
for the Process.StandardOutput property (for .Net 1.1), you'll see an
example that shows that this will deadlock. The online docs at
http://msdn2.microsoft.com/en-us/library/system.diagnostics.process.standardoutput.aspx
don't have the example anymore, but still says the same thing about this
deadlocking.
In any event, you're misunderstanding how the
process.StartInfo.RedirectStandardOutput mechanism works and similar.
Normally the process will write to the console. If you set this
property, then the process class will create its own Stream (probably a
MemoryStream, but it doesn't matter and you shouldn't care). It will
then create a StreamWriter from this stream, and passes that to the
subprocess as the standard output. It will also create a StreamReader
from this stream, and store in the process.StandardOutput property.
It's then your job to use that StreamReader to read the output and put
it wherever you want. In other words, the Process class won't do the
redirection for you. It just gives you the streams you need so that you
can do the redirection.
Gary
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