Thanks for the explanation Hannes! The issue with $ makes sense; I ran into
that some time ago - I can't remember the exact situation, but it was
exactly as you described: the $ introduces ambiguity because it is a valid
character and so could be part of the name of the original function, and
not a separator. Would you be able to point me to the location in the
nashorn source where this mapping/translation is done? It would help me
learn more about the internals of nashorn.
On Thu, May 12, 2016 at 2:12 PM, Hannes Wallnoefer <
hannes.wallnoe...@oracle.com> wrote:
> Hi Vivin,
>
> What you see is some fuzziness in the translation from JS functions to
> Java methods and from there to the stack traces you see.
>
> When we compile a JS function, we create a Java method with the name of
> the function concatenated to the names of its parent functions, using '$'
> as separator. For anonymous functions we use something like L:123 as name
> where 123 is the line of code where the function begins.
>
> This method naming scheme helps a lot in making bytecode easier to debug,
> and to create unique method names within a compilation unit. However, it
> also leads to the stack traces you see, getting f$foo in the first case and
> something like L1:foo in the second case, which is rendered as <anonymous>
> in the stack trace.
>
> Ideally we should reverse this when printing stack traces, displaying only
> the name of the function itself, e.g. "bar" for "foo$bar" and "<anonymous>"
> for "foo$L:3". Unfortunately, "$" is a valid character in a JS identifier,
> so it's not that easy, "foo$bar" may also be the name of the original
> function.
>
> I'm thinking about how to solve this and will probably file an issue for
> it.
>
> Hannes
>
> Am 2016-05-12 um 15:59 schrieb Vivin Suresh Paliath:
>
>> I tried this out on in chrome and I get the expected stack trace there. Is
>> this a bug?
>> On May 6, 2016 3:39 PM, "Vivin Suresh Paliath" <vivin.pali...@gmail.com>
>> wrote:
>>
>> I have the following code:
>>>
>>> *var f = (function() {*
>>> * return function foo() {*
>>> * try {*
>>> * throw new Error();*
>>> * } catch(e) {*
>>> * print(e.stack);*
>>> * }*
>>> * }*
>>> *})();*
>>>
>>>
>>> When I call the function, I get the following stacktrace as expected
>>> (mostly; I was expecting *foo* instead of *f$foo*).
>>>
>>> *Error*
>>> * at f$foo (<shell>:1)*
>>> * at <program> (<shell>:1)*
>>>
>>>
>>> However, if I dynamically construct the function as follows:
>>>
>>> *var f = new Function([], "return function foo() { try { throw new
>>> Error(); } catch(e) { print(e.stack); } }")()*
>>>
>>>
>>> I get:
>>>
>>>
>>> *Error*
>>> * at <anonymous> (<function>:2)*
>>> * at <program> (<shell>:1)*
>>>
>>>
>>> Is there a reason for this discrepancy? Isn't the second version
>>> effectively the same as the first? Also, why is it *f$foo* instead of
>>> *foo* in the first case?
>>>
>>> I am running jdk8u92.
>>>
>>> Thanks!
>>>
>>> --
>>> Ruin untold;
>>> And thine own sadness,
>>> Sing in the grass,
>>> When eve has forgot, that no more hear common things that gleam and pass;
>>> But seek alone to lip, sad Rose of love and ruin untold;
>>> And thine own mother
>>> Can know it as I know
>>> More than another
>>> What makes your own sadness,
>>> Set in her eyes.
>>>
>>> map{@n=split//;$j.=$n[0]x$n[1]}split/:/,"01:11:02".
>>> ":11:01:11:02:13:01:11:01:11:01:13:02:12:01:13:01".
>>> ":11:04:11:06:12:04:11:01:12:01:13:02:12:01:14:01".
>>> ":13:01:11:03:12:01:11:04:12:02:11:01:11:01:13:02".
>>> ":11:03:11:06:11:01:11:05:12:02:11:01:11:01:13:02".
>>> ":11:02:12:01:12:04:11:06:12:01:11:04:12:04:11:01".
>>> ":12:03:12:01:12:01:11:01:12:01:12:02:11:01:11:01".
>>> ":13:02:11:01:02:11:01:12:02";map{print chr unpack"
>>> i",pack"B32",$_}$j=~m/.{8}/g
>>>
>>>
>
--
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