Hi Michael,

Still no luck.


RETURN apoc.date.format(timestamp(),'ms','mm/dd/yyyy');
ans:  "36/08/2017"

RETURN apoc.date.format(timestamp(),'s','mm/dd/yyyy');
"10/26/49657"

Thanks



On Thu, Sep 7, 2017 at 5:50 PM, 'Michael Hunger' via Neo4j <
[email protected]> wrote:

> The last one is correct but without the []
>
> Von meinem iPhone gesendet
>
> Am 07.09.2017 um 23:43 schrieb Sean R <[email protected]>:
>
> Thank you.
>
> Somehow my format is not changing. Am I missing anything ?
>
> 1. RETURN apoc.date.format(timestamp(),'mm/yyyy/dd')
>
> ans: "2017-09-07 21:36:24"
>
> 2. RETURN apoc.date.format(timestamp());
>
> ans: "2017-09-07 21:40:19"
>
> 3. RETURN apoc.date.format(timestamp(),'[ms]','yyyy/mm/dd');
>
>  ans:  "2017/42/07"  -- format is changed but its not correct.
>
> Thanks
>
>
>
>
> On Thursday, September 7, 2017 at 5:29:53 PM UTC-4, Michael Hunger wrote:
>>
>> Use APOC: https://github.com/neo4j-contrib/neo4j-apoc-procedures
>>
>> RETURN apoc.date.format(timstamp());
>>
>> On Thu, Sep 7, 2017 at 11:27 PM, Sean R <[email protected]> wrote:
>>
>>> Greetings.!
>>> Trying to print/return system date and timestamp.
>>>
>>> Following CYPHER gives me  a value of - 1504818368473
>>>
>>> RETURN TIMESTAMP()
>>>
>>> Not sure howto convert into mm/dd/yyyy
>>>
>>> I am using 3.2.2. - community edition.
>>>
>>> Thanks
>>>
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