public double getDistancia(double latitude, double longitude, double
latitudePto, double longitudePto){ double dlon, dlat, a, distancia; dlon =
longitudePto - longitude; dlat = latitudePto - latitude; a = Math.pow(Math.
sin(dlat/2),2) + Math.cos(latitude) * Math.cos(latitudePto) * Math.pow(Math.
sin(dlon/2),2); distancia = 2 * Math.atan2(Math.sqrt(a), Math.sqrt(1-a));
return 6378140 * distancia; /* 6378140 is the radius of the Earth in
meters*/ }https://en.wikipedia.org/wiki/Distance_(graph_theory) On Mon, Sep 3, 2018 at 7:02 AM Youssef Mourchid <[email protected]> wrote: > Hello, > > if can anyone help me to find a way to compute the diameter of a graph > with different categories of edges i will be very thankful. > > In my case my graph contains three categories of nodes (Person, speech, > Time) and 6 relationships. > > -- > You received this message because you are subscribed to the Google Groups > "Neo4j" group. > To unsubscribe from this group and stop receiving emails from it, send an > email to [email protected]. > For more options, visit https://groups.google.com/d/optout. > -- JOSÉ RIBAMAR FERREIRA JUNIOR ANALISTA DE SISTEMAS Joinville - SC (47) 9844-23634 (47) 3436-4774 [email protected] [email protected] https://www.linkedin.com/in/josé-r-f-junior-b72b6b1a/ -- You received this message because you are subscribed to the Google Groups "Neo4j" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. For more options, visit https://groups.google.com/d/optout.
