As long as you dont exceed the RMS current rating of the LED, they will outlast any other type of illuminating device being replaced, especially incandescent.
>From the schematic, there are already diodes in the path, so if an LED was installed backwards there's no possible way it can get damaged from reverse-polarity. However, the LED wont illuminate if backwards. LEDs have roughly a 2V drop, so you *will* need to add a series resistor; just need to calculate the rough value. The supply is 6.3 VAC (about 9V peak) , and there are 2 diodes in the path. So, the resistor's voltage drop must be about (9-2-0.7 - 0.7 = 5.6 volts). If you get larger diodes that operate at 20mA (should be a good replacement for incandescent lamp), your resistor will be around 270 ohms. Use a 1/4 watt resistor. Obviously you will need to experiment with a few different resistor values to get the desired brightness, so try some values between 220 and 470 ohms. -- You received this message because you are subscribed to the Google Groups "neonixie-l" group. To unsubscribe from this group and stop receiving emails from it, send an email to neonixie-l+unsubscr...@googlegroups.com. To post to this group, send an email to neonixie-l@googlegroups.com. To view this discussion on the web, visit https://groups.google.com/d/msgid/neonixie-l/6ccc7136-e272-442c-a81e-43f93556783c%40googlegroups.com. For more options, visit https://groups.google.com/d/optout.
