I cant figure out why there is a duplicate column of LEDs on the far right side.
The IC is probably a custom BCD-to-segment driver specifically for discrete LEDs. There is only 1 resistor on the board, so the driver IC probably does the current-limiting. I'm fairly certain the IC is not MOS/CMOS, so it's probably still OK (not damaged by ESD), and it should not be too difficult to reverse-engineer the connector pinout. If the LEDs are wired in-series, you can estimate the required power-supply voltage by measuring the forward voltage of 1 LED (roughly 2V @ 10mA). If they are parallel, I would assume 5V operation. The 120 ohm resistor would give 23mA thru an LED that has a 2.2V drop and a 5V supply. See how many LEDs are connected to it. Nice find, and I hope you win the auction. -- You received this message because you are subscribed to the Google Groups "neonixie-l" group. To unsubscribe from this group and stop receiving emails from it, send an email to neonixie-l+unsubscr...@googlegroups.com. To post to this group, send an email to neonixie-l@googlegroups.com. To view this discussion on the web, visit https://groups.google.com/d/msgid/neonixie-l/71eeef16-ca6c-4c1d-83c2-074fe463c81f%40googlegroups.com. For more options, visit https://groups.google.com/d/optout.
