Your solution resolve my problem partially, I have success to print the
value but my real objective is save the value in a buffer, and when i try
do this, with your method, i don't have success. The printf line is just to
verify the saved value.
About the memory allocated, i think this resolve
size_t test = 64;
int *sp = malloc(test);
memcpy(sp, vars->val.string, vars->val_len);
int *teste = htonl(*sp);
printf("value #%d is a string: %x \n", count++, teste);
free(sp);
2013/10/3 Magnus Fromreide <ma...@lysator.liu.se>
>
> On Thu, 2013-10-03 at 18:14 +0000, Rafael Ratacheski wrote:
> > Hello, I'm having troubles in request and save the value of the
> > ipNetToMediaPhysAddress OID.
> >
> > My routine get the MAC Adress, but only a half of the value.
> >
> > What I'm doing wrong? Can you help me?
> >
> > if (vars->type == ASN_OCTET_STR) {
> > u_long *sp = malloc(1+id_len);
>
> What is the value of id_len? I'll guess it is 6 for further analysis.
> In that case you have just allocated 7 bytes of memory for a 32-bit
> unsigned integer (or a 64-bit one - even worse...)
>
> > memcpy(sp, vars->val.string, id_len);
>
> You then copy the six bytes of the mac address to the newly allocated
> memory. This is actually correct, but rather odd given the types.
>
> > const char *teste = htonl(*sp);
>
> And then you assign the byte swapped value of the first four octets of
> the mac address to the pointer variable teste. This is undefined
> according to the C standard.
>
> > printf("value #%d is a string: %x \n", count++, teste);
>
>
> Then you print the address that teste refers to,
>
> > free(sp);
>
> Finally you frees the allocated memory. Good.
>
> > }
> >
>
> So, to answer your questions:
>
> > What am I doing wrong?
>
> Just about everything.
>
> > Can you help me?
>
> Well...
> I would write that snippet as
>
> if (vars->type == ASN_OCTET_STR) {
> int i;
> printf("value #%d is a string: ", count++);
> for (i = 0; i < vars->val_len; ++i)
> printf("%x", vars->val.string[i]);
> puts("");
> }
>
> (Ok, I probably would put it in a char buffer and print it all at once
> rather than repeatedly call printf but this is the easy version)
>
> ... but that probably isn't what you really wanted to know.
>
> /MF
>
>
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