Thanks JP. Functions you have provided are very useful.
-Abhishek
On Tue, 2007-06-26 at 12:30, Jayaprakasha Guddenahalli Naganna wrote:
> Treat BITS as just OCTET STRING.
> Example API's for processing bits from char* variable,
> Call this function by passing *val* from set_handler,
> /*
> * bits -- set val
> * pos -- which bit you want to read from set val
> */
> int bit_get(const unsigned char *bits, int pos) {
> unsigned int mask;
> int i;
>
> mask = 0x80;ple API's for processing bits from char* variable,
> for (i=0; i < (pos % 8); i++)
> mask = mask >> 1;
>
> return (((mask & bits[(int)(pos / 8)]) == mask) ? 1 : 0);
> }
>
> Call this function by passing *ret_val* from get_handler,
> /*
> * bits -- ret value from get_handler from function
> * pos -- which bit you want to set
> */
> void bit_set(unsigned char *bits, int pos) {
> unsigned char mask;
> int i;
>
> mask = 0x80;
> for (i = 0; i < (pos % 8); i++)
> mask = mask >> 1;
>
> bits[pos / 8] = bits[pos / 8] | mask;
> return;
> }
> Example snmpset command,
> Snmpset column.<index> x 28
> OR
> snmpset column.<index> b proxyServer,registrarServer
>
> >> I suppose that numbering would be:
> >> 8 7 6 5 4 3 2 1
> >> - - X - X - - -
> >> If these bits would be set then index 0 of the octet string should be
>
> >> equal to: 0x28.
> >> Is that correct?
> [JP] yes
> -----Original Message-----
> From: [EMAIL PROTECTED]
> [mailto:[EMAIL PROTECTED] On Behalf Of
> Abhishek Mishra
> Sent: Tuesday, June 26, 2007 11:51 AM
> To: [email protected]
> Cc: Abhishek Mishra
> Subject: How to convert BITS data into OCTET String
>
> Hi,
>
> We have a column in the table that have datatype of BITS. After
> compilation of the MIB file, it is converted into a character array. I
> found some information in the RFC# 3416/3417 regarding the conversion
> but could not understand well how to convert BITS field into the octet
> string. Following is the BITS field we are using:
>
> SYNTAX BITS {
> other(0),
> userAgent(1),
> proxyServer(2),
> redirectServer(3),
> registrarServer(4)
> }
>
> Now, I have to set bit 2 (proxyServer) and 4 (registrarServer) into the
> octet string.
> Please guide me how the conversion would actually take place.
>
> I suppose that numbering would be:
> 8 7 6 5 4 3 2 1
> - - X - X - - -
>
> If these bits would be set then index 0 of the octet string should be
> equal to: 0x28.
> Is that correct?
>
> Kind Regards,
> -Abhishek
>
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