On 11/14/2016 02:43 AM, Daniel Borkmann wrote:
> In mlx5e_create_rq(), when creating a new queue, we call bpf_prog_add() but
> without checking the return value. bpf_prog_add() can fail, so we really

Didn't know this, thanks for noticing, I wonder why taking a reference for an 
object would fail ?
especially when someone is requesting from the driver to take a reference to it 
ndo_xdp_set ?! sounds like a bad design.

Anyway I will check that later.

> must check it. Take the reference right when we assign it to the rq from
> priv->xdp_prog, and just drop the reference on error path. Destruction in
> mlx5e_destroy_rq() looks good, though.
> 
> Fixes: 86994156c736 ("net/mlx5e: XDP fast RX drop bpf programs support")
> Signed-off-by: Daniel Borkmann <dan...@iogearbox.net>
> ---
>  drivers/net/ethernet/mellanox/mlx5/core/en_main.c | 14 +++++++++++---
>  kernel/bpf/syscall.c                              |  1 +
>  2 files changed, 12 insertions(+), 3 deletions(-)
> 
> diff --git a/drivers/net/ethernet/mellanox/mlx5/core/en_main.c 
> b/drivers/net/ethernet/mellanox/mlx5/core/en_main.c
> index 84e8b25..2b83667 100644
> --- a/drivers/net/ethernet/mellanox/mlx5/core/en_main.c
> +++ b/drivers/net/ethernet/mellanox/mlx5/core/en_main.c
> @@ -489,7 +489,16 @@ static int mlx5e_create_rq(struct mlx5e_channel *c,
>       rq->channel = c;
>       rq->ix      = c->ix;
>       rq->priv    = c->priv;
> +
>       rq->xdp_prog = priv->xdp_prog;

Why keeping this assignment ? just test priv->xdp_prog.

> +     if (rq->xdp_prog) {
> +             rq->xdp_prog = bpf_prog_inc(rq->xdp_prog);
> +             if (IS_ERR(rq->xdp_prog)) {
> +                     err = PTR_ERR(rq->xdp_prog);
> +                     rq->xdp_prog = NULL;
> +                     goto err_rq_wq_destroy;
> +             }
> +     }

Try this, simpler and less indentations:
 
rq->xdp_prog = priv->xdp_prog ? bpf_prog_inc(priv->xdp_prog) : NULL;
if (IS_ERR(rq->xdp_prog)) {
        err = PTR_ERR(rq->xdp_prog);
        rq->xdp_prog = NULL;
        goto err_rq_wq_destroy;
}

Saeed.

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