On Sat, Aug 05, 2017 at 08:31:09PM +0800, Xin Long wrote:
> Chen Wei found a kernel call trace when modprobe sctp_probe with
> bufsize set with a huge value.
>
> It's because in sctpprobe_init when alloc memory for sctpw.fifo,
> the size is got from userspace. If it is too large, kernel will
> fail and give a warning.
Yes but sctp_probe can only be loaded by an admin and it would happen
only during modprobe. It's different from the commit mentioned below, on
which any user could trigger it.
>
> As there will be a fallback allocation later, this patch is just
> to fail silently and return ret, just as commit 0ccc22f425e5
> ("sit: use __GFP_NOWARN for user controlled allocation") did.
>
> Reported-by: Chen Wei <weic...@redhat.com>
> Signed-off-by: Xin Long <lucien....@gmail.com>
> ---
> net/sctp/probe.c | 2 +-
> 1 file changed, 1 insertion(+), 1 deletion(-)
>
> diff --git a/net/sctp/probe.c b/net/sctp/probe.c
> index 6cc2152..5bf3164 100644
> --- a/net/sctp/probe.c
> +++ b/net/sctp/probe.c
> @@ -210,7 +210,7 @@ static __init int sctpprobe_init(void)
>
> init_waitqueue_head(&sctpw.wait);
> spin_lock_init(&sctpw.lock);
> - if (kfifo_alloc(&sctpw.fifo, bufsize, GFP_KERNEL))
> + if (kfifo_alloc(&sctpw.fifo, bufsize, GFP_KERNEL | __GFP_NOWARN))
> return ret;
>
> if (!proc_create(procname, S_IRUSR, init_net.proc_net,
> --
> 2.1.0
>
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