On Monday 19 February 2007 16:14, Eric Dumazet wrote:
>
> Because O(1) is different of O(log(N)) ?
> if N = 2^20, it certainly makes a difference.
> Yes, 1% of chains might have a length > 10, but yet 99% of the lookups are
> touching less than 4 cache lines.
> With a binary tree, log(2^20) is 20. or maybe not ? If you tell me it's 4,
> I will be very pleased.
>

Here is the tcp ehash chain length distribution on a real server :
ehash_addr=0xffff810476000000
ehash_size=1048576
333835 used chains, 3365 used twchains
Distribution of sockets/chain length
[chain length]:number of sockets
[1]:221019 37.4645%
[2]:56590 56.6495%
[3]:21250 67.4556%
[4]:12534 75.9541%
[5]:8677 83.3082%
[6]:5862 89.2701%
[7]:3640 93.5892%
[8]:2219 96.5983%
[9]:1083 98.2505%
[10]:539 99.1642%
[11]:244 99.6191%
[12]:112 99.8469%
[13]:39 99.9329%
[14]:16 99.9708%
[15]:6 99.9861%
[16]:3 99.9942%
[17]:2 100%
total : 589942 sockets

So even with a lazy hash function, 89 % of lookups are satisfied with less 
than 6 compares.

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