Hi Andi! On 6 Mar 2007, at 15:45, Andi Kleen wrote:
And it's pretty neat, too. Hint: (y+1)**3 = y**3 + 3*y**2 + 3*y + 1. The algorithm is exactly the same as for calculating the cubic root on paper, digit by digit. I found that algo in the school notebook of my grandpa (late 1920ies), a pity that it's not taught anymore... pocket calculators _do_ have downsides ;-)<rant> Let me see... You throw code like that and expect someone to actually understand it in one year, and be able to correct a bug ?To be honest I don't expect any bugs in this function.</rant>Please add something, an URL or even better a nice explanation, per favor...It's straight out of Hacker's delight which is referenced in the commitlog.
Ciao, Roland -- TU Muenchen, Physik-Department E18, James-Franck-Str., 85748 Garching Telefon 089/289-12575; Telefax 089/289-12570 -- CERN office: 892-1-D23 phone: +41 22 7676540 mobile: +41 76 487 4482 -- Any society that would give up a little liberty to gain a little security will deserve neither and lose both. - Benjamin Franklin -----BEGIN GEEK CODE BLOCK----- Version: 3.12GS/CS/M/MU d-(++) s:+ a-> C+++ UL++++ P+++ L+++ E(+) W+ !N K- w--- M + !V Y+
PGP++ t+(++) 5 R+ tv-- b+ DI++ e+++>++++ h---- y+++ ------END GEEK CODE BLOCK------
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