On Thu, Feb 4, 2016 at 8:51 AM, Alexander Duyck
<alexander.du...@gmail.com> wrote:
> On Thu, Feb 4, 2016 at 3:08 AM, David Laight <david.lai...@aculab.com> wrote:
>> From: Tom Herbert
>>> Sent: 03 February 2016 19:19
>> ...
>>> +     /* Main loop */
>>> +50:  adcq    0*8(%rdi),%rax
>>> +     adcq    1*8(%rdi),%rax
>>> +     adcq    2*8(%rdi),%rax
>>> +     adcq    3*8(%rdi),%rax
>>> +     adcq    4*8(%rdi),%rax
>>> +     adcq    5*8(%rdi),%rax
>>> +     adcq    6*8(%rdi),%rax
>>> +     adcq    7*8(%rdi),%rax
>>> +     adcq    8*8(%rdi),%rax
>>> +     adcq    9*8(%rdi),%rax
>>> +     adcq    10*8(%rdi),%rax
>>> +     adcq    11*8(%rdi),%rax
>>> +     adcq    12*8(%rdi),%rax
>>> +     adcq    13*8(%rdi),%rax
>>> +     adcq    14*8(%rdi),%rax
>>> +     adcq    15*8(%rdi),%rax
>>> +     lea     128(%rdi), %rdi
>>> +     loop    50b
>>
>> I'd need convincing that unrolling the loop like that gives any significant 
>> gain.
>> You have a dependency chain on the carry flag so have delays between the 
>> 'adcq'
>> instructions (these may be more significant than the memory reads from l1 
>> cache).
>>
>> I also don't remember (might be wrong) the 'loop' instruction being executed 
>> quickly.
>> If 'loop' is fast then you will probably find that:
>>
>> 10:     adcq 0(%rdi),%rax
>>         lea  8(%rdi),%rdi
>>         loop 10b
>>
>> is just as fast since the three instructions could all be executed in 
>> parallel.
>> But I suspect that 'dec %cx; jnz 10b' is actually better (and might execute 
>> as
>> a single micro-op).
>> IIRC 'adc' and 'dec' will both have dependencies on the flags register
>> so cannot execute together (which is a shame here).
>>
>> It is also possible that breaking the carry-chain dependency by doing 32bit
>> adds (possibly after 64bit reads) can be made to be faster.
>
> If nothing else reducing the size of this main loop may be desirable.
> I know the newer x86 is supposed to have a loop buffer so that it can
> basically loop on already decoded instructions.  Normally it is only
> something like 64 or 128 bytes in size though.  You might find that
> reducing this loop to that smaller size may improve the performance
> for larger payloads.
>
I saw 128 to be better in my testing. For large packets this loop does
all the work. I see performance dependent on the amount of loop
overhead, i.e. we got it down to two non-adcq instructions but it is
still noticeable. Also, this helps a lot on sizes up to 128 bytes
since we only need to do single call in the jump table and no trip
through the loop.

Tom

> - Alex

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