Maybe this would do it (as a shell script):
#! /bin/sh
for $i in `find .`; do
cp $i $i.old
cat $i.old | sed -e "s/MarketingWorks\/Collard
Associates/MarketingWorks" > $i
next;
I am NOT a shell script guru- you can tell because my for loop syntax is
wrong, and I'm not sure what the proper way to write it is. I hope I
get my idea across, though. You might run it as `script 2> /dev/null`
because it will generate an error message for every directory under ./
as I couldn't figure out a way to get `find` to list only files, or
`ls -R` to not print out directory names.
With this pseudo-script, you also get backups of your HTML files
(with a .old extension) in case it screws up. If it works, then you can
rm `find . |grep .old`
to recusively remove all old files. I think.
-Matt Stegman
<[EMAIL PROTECTED]>
On Thu, 2 Sep 1999, James Stewart wrote:
> Been investigating the problem I posted yesterday a bit more, and have a
> slightly better way of expressing it now ;)
>
> What I want to do is like issuing:
>
> grep -r MarketingWorks\/Collard Associates /home/httpd/marketingworks.co.uk
>
> but instead of listing the results I want to replace it with simply
> MarketingWorks
>
> Another way of looking at it is issuing perl's
> s/MarketingWorks\/Collard Associates/MarketingWorks/;
>
> but recursively through the directory structure.
>
> Can anyone suggest how to do this?
>
> James.
> --
> James Stewart | Britlinks | The Phantom Tollbooth
> [EMAIL PROTECTED] | http://www.britlinks.co.uk | http://www.tollbooth.org
>
> Sixpence None The Richer UK -- http://www.britlinks.co.uk/sixpence/
>
