> Is the new `std/channels` the new implementation?

Yes.

> Now having tried the new std/channels library and seeing that the new 
> FlowVar[T] can be nothing but a synonym for a new unbuffered Channel[T] with 
> all the "compiler magic" applied in the implementation of Isolated[T] which 
> it uses, it doesn't look so hard to write a std/threadpool.

Now you understand. :-)

Reply via email to