Here is a slightly cleaned up version of the code with comments as to why
it's doing what it does. (the `this.result` code didn't affect the output
and was a distraction since it was polluting the global scope)
function addasync(no1, no2, callback) {
res = no1 + no2;
callback(false, res); // Will log the first 3
process.nextTick(function () { // nextTick returns right away, so we
don't get 3 yet
callback(true, res); // Will log the last 3
});
};
function addsync(no1, no2) {
return (no1 + no2);
}
addasync(1, 2, function(err, res) {
console.log(res); // Will get called twice, once before returning and once
in the nextTick
});
console.log(addsync(4, 2)); // Will log the 6 in the middle
On Wed, Jun 6, 2012 at 8:31 AM, Anand George <mranandgeo...@gmail.com>wrote:
> Hi!
>
> Have been reading up on process.nextTick and found this one rather odd.
> It's forcing the calling function to run again.
>
> function addasync(no1, no2, result)
> {
> res = no1 + no2;
> this.result = result(false, res);
> process.nextTick(function() {
> this.result = result(true, res);
> });
> };
>
> addasync(1, 2, function(err, res) {
> console.log(res);
> });
>
> function addsync(no1, no2) {
> return (no1 + no2);
> }
>
> console.log(addsync(4, 2));
>
> When I run this code I get the following output.
>
> 3
> 6
> 3.
>
> Any ideas why this could be happening.
>
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