Not at all. You dont need any agent at Node3. Its an intermediate node. It just forwards the packets.
Regards, Ubaid 2009/5/28 tan cam <bem...@yahoo.com> > > Thank you Ubaid, > Your explaint is very clearly, but I have some question. > Ubaid, I have a topology, and I have 4 agents: UDP1 agent on node1, UDP2 > agent on node2, sink14 on node4 (connect to UDP1) and sink24 on node4 > (connect to UDP2). Must I have any UDP agent on node3? > > Node1___________Node3___________________Node4 > / > / > / > / > / > / > Node2______/ > Thanks Ubaid, againt. > > =========================== > Nguyen Tan Cam > > HCMUS > =========================== > > > > --- On Thu, 5/28/09, obaid abbasi <obaidabb...@gmail.com> wrote: > > > From: obaid abbasi <obaidabb...@gmail.com> > > Subject: Re: [ns] Please help me, I want to count the number of packet, > that the intermediate node recieved. > > To: "tan cam" <bem...@yahoo.com> > > Date: Thursday, May 28, 2009, 2:22 PM > > Hi, > > > > If you are using UDP agent then you have to look for file > > udp.cc and then change its receive function. whichever agent > > you are using, you have to make changes in its > > "cc" file. > > > > Hope it works. > > > > > > Best Regards, > > Ubaid > > > > 2009/5/28 tan cam <bem...@yahoo.com> > > > > > > > > Thank you, Obaid Abbasi, > > > > But I don't know, what agent that I modify it's > > recv() function. > > > > More information that, I want to count the received packet > > on each node, and my counting have a frequency. > > > > example: if frequency is 10s, and array of counting result > > is count[]: > > > > from second 1 to second 10, I have count[0] = > > 102 packets > > > > from second 11 to second 20, I have count[1] = > > 15 packets > > > > ... > > > > Please help me, > > > > Thank you so much. > > > > > > > > =========================== > > > > Nguyen Tan Cam > > > > HCMUS > > > > =========================== > > > > > > > > > > > > > > > > --- On Tue, 5/26/09, obaid abbasi > > <obaidabb...@gmail.com> > > wrote: > > > > > > > > > From: obaid abbasi <obaidabb...@gmail.com> > > > > > Subject: Re: [ns] Please help me, I want to > > count the number of packet, that the intermediate node > > recieved. > > > > > To: "tan cam" <bem...@yahoo.com> > > > > > Cc: ns-users@isi.edu > > > > > Date: Tuesday, May 26, 2009, 6:48 PM > > > > > Hi, > > > > > > > > > > > > > > > This is very simple. In the recv(Packet* p, > > > > > Handler*) function, access the ip header hdr_ip* iph > > > > > = hdr_ip::access(p) > > > > > and then write an "if condition" to check > > the > > > > > packet received at node 2. Increment the counter in > > > > > "if" block every time a packet is received > > at node > > > > > 2. > > > > > > > > > > > > > > > > > > > > Best Regards, > > > > > Ubaid > > > > > > > > > > > > > > > 2009/5/26 tan cam <bem...@yahoo.com> > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > Hi everyone, > > > > > > > > > > I have the problem when I try to count the number of > > > > > packet, that the intermediate node received. > > > > > > > > > > I have a topology, that have 4 nodes (following > > figure): > > > > > > > > > > node1_________Node3___________________Node4 > > > > > > > > > > / > > > > > > > > > > / > > > > > > > > > > / > > > > > > > > > > / > > > > > > > > > > node2______/ > > > > > > > > > > That mean, Node1 link to Node3 > > > > > > > > > > Node2 link to Node3 > > > > > > > > > > Node3 link to Node4 > > > > > > > > > > I have two agent that send packet from Node1 to Node4 > > and > > > > > Node2 to node4. > > > > > > > > > > (example Node1 ping node4 and Node2 ping Node4). > > > > > > > > > > Of course, all of packet through Node3 before arrive > > > > > node4. > > > > > > > > > > My problem is: > > > > > > > > > > I want to count the number of packet, that Node3 > > > > > (intermediate node) received during Node1 sent packet > > to > > > > > node4 and node2 sent packet to node4. > > > > > > > > > > I use NS2 version 2.33 for Redhat Linux 4.0 > > > > > > > > > > > > > > > > > > > > Thank you so much. > > > > > > > > > > =========================== > > > > > > > > > > Nguyen Tan Cam > > > > > > > > > > > > > > > > > > > > HCMUS > > > > > > > > > > =========================== > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > >
