Hi Otared and Wolgang,
Thanks for the answers. In fact, being familiar with Python and not at all
with Lua, I didn't have the reflex to think of using a mathematical
function which gives the remainder in the Euclidean division by 10, it's
strange !!
Fabrice
Le jeu. 24 août 2023 à 04:06, Wolfgang Schuster <
wolfgang.schuster.li...@gmail.com> a écrit :
> Otared Kavian schrieb am 24.08.2023 um 01:04:
>
> Hi Fabrice,
>
> As Wolfgang points out, it is indeed possible to fill-in your table with
> Lua: maybe you were wondering how to fill the columns 2, 3 and 4. In this
> case you need to use the Lua function math.mod as in the following, which
> is a completed version of what Wolfgang sent:
>
>
> I guess I completely missed the units digit part :)
>
> %% begin filling-with-lua.tex
> \starttext
>
> \startluacode
> context.startxtable{ align = "middle,lohi", bodyfont = "9pt", framecolor =
> "black" }
> context.startxrow{ background = "color", backgroundcolor = "lightgray"
> }
> context.startxcell{ nx = 4 }
> context("Units digit of")
> context.stopxcell()
> context.stopxrow()
> context.startxrow()
> context.startxcell{ width = "1cm" }
> context.im("a")
> context.stopxcell()
> context.startxcell{ width = "1cm" }
> context.im("a^2")
> context.stopxcell()
> context.startxcell{ width = "1cm" }
> context.im("b")
> context.stopxcell()
> context.startxcell{ width = "1cm" }
> context.im("2b^2")
> context.stopxcell()
> context.stopxrow()
> for i = 0,9 do
> context.startxrow()
> for j = 1,4 do
> context.startxcell()
> if j == 1 then
> context(i)
> elseif j == 2 then
> context(math.mod(i*i,10))
> elseif j == 3 then
> context(i)
> else
> context(math.mod(2*i*i,10))
> end
> context.stopxcell()
> end
> context.stopxrow()
> end
>
>
> I would drop the column check in this case.
>
> for i = 0,9 do
> context.startxrow()
> context.startxcell()
> context(i)
> context.stopxcell()
> context.startxcell()
> context(math.mod(i*i,10))
> context.stopxcell()
> context.startxcell()
> context(i)
> context.stopxcell()
> context.startxcell()
> context(math.mod(2*i*i,10))
> context.stopxcell()
> context.stopxrow()
> end
>
> Wolfgang
>
>
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