Thanks Aditya, but it does not work what it should?
With:
\defineenumeration[demo][text={Demostració.\space},number=no,
location=serried,width=fit,headstyle=italic,indentnext=yes,
between=\blank,textdistance=.5em,closesymbol={\mathematics{\Box}},
style=normal,indenting=yes]
and
\starttext
\startdemo Si $\text{area}(u) = N$ i $\text{area}(v) = M$, aleshores
\startformula
\startmathalignment
\NC u \NC = \prod_{i=1}^N x_i^{-1} r_i x_i, \NR[+]
\NC v \NC = \prod_{j=1}^M y_j^{-1} s_j y_j, \NR[+]
\stopmathalignment
\stopformula%
per a alguns $x_i, y_j \in F(A)$, $r_i, s_j \in R$, on aquestes
igualtats són dins el grup lliure $F(A)$. Com que $w = u v$ també dins
el grup lliure, tenim que
\placeformula[-] \startformula \startsplit
\NC w = u v \NC = \bigl( \prod_{i = 1}^N x_i^{-1} r_i x_i \bigr) \cdot
\bigl( \prod_{j=1}^M y_j^{-1} s_j y_j \bigr) \NR
\NC \NC = (x_1^{-1} r_1 x_1)\cdots (x_N^{-1} r_N x_N) \cdot (y_1^{-1}
s_1 y_1) \cdots (y_M^{-1} s_M y_M) \NR
\NC \NC = \prod_{k=1}^{M+N} z_k^{-1} t_k z_k
\stopsplit \stopformula
on
\startformula
z_k = \startcases
\NC x_k \MC 1 \leq k \leq N \NR
\NC y_{k-N} \MC N+1 \leq k \leq N+M, \NR
\stopcases t_k = \startcases
\NC r_k \MC 1 \leq k \leq N \NR
\NC s_{k-N} \MC N+1 \leq k \leq N+M. \NR
\stopcases
\stopformula
Llavors, per definició, $\text{area}(w) \leq N+M = \text{area}(u) +
\text{area}(v)$.
\stopdemo
\stoptext
I have that "per a alguns" is indenting but "on" is not.
Why?
Xan.
PS: Please, CCme
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