Am 10.06.2009 um 11:47 schrieb Nicolas Girard:
* If so, I don't understand how can \dosetuparrangement{3}{1}{6}{4}{2}
give 1|2|3 // 4|5|6 . What's the rationale ? Why no page 5 among the
arguments of \dosetuparrangement ?
The placement of the pages is defined \pusharrangedpageTHREESIDE, the
values
above mean:
• number of columns: 3
• number of rows: 1
• total number of pages: 6 (ConTeXt collects 6 pages and arrange them
before
they are written to the pdf file but in Willi's code 3 had been
enough)
• number of crop marks in x direction: 4 (columns + 1)
• number of crop mark in y direction: 2 (rows + 1)
* What if one wants to fold the resulting brochure ? How to adapt the
code (besides by try and error) for the resulting arrangement to be
3|6|1 // 2|4|5 ?
The page order in a brochure is 5|6|1 and 2|3|4.
Wolfgang
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