Is there a convenient way within a Lua block to determine the current
file name and line number of the source file being processed by ConTeXt?
For example: (test.tex)
---------------------------------
\def\ShowLineNumber{%
\ctxlua{print('current line number:', tex.current_line_number())
print('current file:', tex.current_file_name())}}
\starttext
a line
\ShowLineNumber
another line
\ShowLineNumber
\stoptext
---------------------------------
With the following displayed:
---------------------------------
current line number: 6
current file: test.tex
current line number: 9
current file: test.tex
---------------------------------
I've considered hooking into the open_read_file callback and tracking
the file name and line number (via reader) myself. But that seems a bit
heavy handed if the file name and line number information are available
more directly. And since that information is needed for error
reporting, I'm thinking there's a good chance it is accessible.
(Just in case you're interested, the purpose of this is to be able to
assemble code segments during the ConTeXt processing into external files
with #line directives ala the C preprocessor. That way if the
subsequent compilation of the external file results in an error, the
error message can refer back to the line of code in the ConTeXt source
file. This is part of the literate programming module that Kevin
Robbins has been describing in another thread.)
Thanks,
Tad
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