On 22-9-2010 2:06, Otared Kavian wrote:
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Note that $\int_{0}^{2\pi} \sin(x)dx = 0$, while
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\int_{0}^{2\pi} \sin^2(x)dx = \pi \qquad \mbox{and}\qquad \sqrt{4}= 2.
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Afaik nothing was changed so I'll wait for Taco's comments before I
start messing around.
Hans
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