Hello,
thanks for the answer - wikified
(http://wiki.contextgarden.net/%5Cdefinestrcutureconversionset).
BTW:
I created a new page.
But the caption is
"\definestrcutureconversionset" instead of
"Reference/en/definestrcutureconversionset".
And also, the item in the reference is
"\definestrcutureconversionset" instead of
"Reference/en/definestrcutureconversionset"
(http://wiki.contextgarden.net/Category:Reference/en).
I have no idea how to correct it, or how to determine the location for a new
page to be created.
Best regards,
Lukas
On Thu, 16 Feb 2012 21:39:04 +0100, Wolfgang Schuster
<schuster.wolfg...@googlemail.com> wrote:
Am 16.02.2012 um 10:57 schrieb Procházka Lukáš Ing. - Pontex s. r. o.:
Hello,
I cannot find any valid info (reference) about use of the command
\definestructureconversionset. I just have some examples.
Could anyone explain how these commands should work?
\definestructureconversionset[name-of-conversion-set][par1,par2,...][Par1,Par2,...]
\definestructureconversionset[name-of-conversion-set][][Par1,Par2,...] % 1St
par. set empty
\definestructureconversionset[name-of-conversion-set][par1,par2,...][] % 2Nd
par. set empty
\definestructureconversionset[name-of-conversion-set][par1,par2,...] % 2Nd
argument omitted
\definestrcutureconversionset[..1..][..,..2..,..][..3..]
1. Name of the conversion set
2. List with explicit settings for certain headings
3. Default setting if no explicit conversion is set
The first argument is just the name which is used as argument for
sectionconverionset in \setuphead for prefixconverionset in \setupcaption,
\setupenumeration etc. The name of the conversion can be prefixed with the name
of a sectionblock, e.g.
\definestructureconverionset[bodypart:myconversion][A,I,n,R][numbers]
With the second argument you can set a conversion of the counter for the
headings, the list starts always with the \part level and continues with
\chapter etc. but it’s possible leave entries empty.
With the third argument one can set a default value which is used when no value
for a heading is set with the second argument.
Wolfgang
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___________________________________________________________________________________
If your question is of interest to others as well, please add an entry to the
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