On 09/08/12 09:37, Steffen Wolfrum wrote:
Hi,
for nice linebreaking we can adjust math formulas by the use of NC, NR
alignment.
But if someone only wants long formulas to fit in a defined area, and want them
to break automatically ... is there a handy solution?
(Below are examples that don't work)
Thanks,
Steffen
-------
\starttext
\placeformula
\startformula[9pt]
I=\big\{\lambda u(x_0-\pi^H K)+(1-\lambda)[\pi^L u(x_0-K+(1-\pi^L)Z_{L'})
+(1-\pi^L)u(x_0-\pi^L Z_{L'})]\big\}-\big\{\pi^U u(x_0-K+(1-\pi^U)Z_{U'})
+(1-\pi^U)u(x_0-\pi^U Z_{U'})\big\}.
\stopformula
\defineframedtext
[defbackground]
[width=10cm,
frame=on,
location=paragraph]
\startdefbackground
\placeformula
\startformula[9pt]
I=\big\{\lambda u(x_0-\pi^H K)+(1-\lambda)[\pi^L u(x_0-K+(1-\pi^L)Z_{L'})
+(1-\pi^L)u(x_0-\pi^L Z_{L'})]\big\} -\big\{\pi^U u(x_0-K+(1-\pi^U)Z_{U'})
+(1-\pi^U)u(x_0-\pi^U Z_{U'})\big\}.
\stopformula
\stopdefbackground
\definelayer[mylayer]
\setlayerframed
[mylayer]
[x=25mm,
y=85mm,
height=43.5mm,
width=10cm,align=block]
{
\placeformula
\startformula[9pt]
I=\big\{\lambda u(x_0-\pi^H K)+(1-\lambda)[\pi^L u(x_0-K+(1-\pi^L)Z_{L'})
+(1-\pi^L)u(x_0-\pi^L Z_{L'})]\big\} -\big\{\pi^U u(x_0-K+(1-\pi^U)Z_{U'})
+(1-\pi^U)u(x_0-\pi^U Z_{U'})\big\}.
\stopformula
}
\setupbackgrounds[page][background=mylayer]
\stoptext
When I needed something like that, I used \allowbreak with inlinemath.
In your case, you could do:
\bTABLE[frame=on,align=right,width=10cm]
\bTR
\bTD
$I=\big\{\lambda u(x_0-\pi^H K)\allowbreak+(1-\lambda)[\pi^L
u(x_0-K+(1-\pi^L)Z_{L'})\allowbreak+(1-\pi^L)u(x_0-\pi^L
Z_{L'})]\big\}\allowbreak -\big\{\pi^U
u(x_0-K+(1-\pi^U)Z_{U'})\allowbreak+(1-\pi^U)u(x_0-\pi^U Z_{U'})\big\}.$
\eTD
\eTR
\eTABLE
This will just flow it like regular text. I don't know if this is good
enough for your needs. If not, you can add another way to your list of
ways ;-).
-- Prash
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