On 4/18/2015 10:24 PM, Otared Kavian wrote:
Hi again Wolfgang,
Thanks to your hint, I could solve the problem…
In case someone else would encounter a similar problem to solve, below is a
macro which chooses an element from a list, it creates a control sequence (CS)
containing that element and it keeps the CS until the next time the macro is
invoked again to choose another element.
Thanks again and best regards: OK
%%%% begin choose-element.tex
\setuprandomize[1989] % set a seed
\starttext
% here is a list from which a name is chosen
\startluacode
ListOfNames = {'F', 'G', 'u', 'v', 'W'}
\stopluacode
% this macro has two arguments:
% the first argument is the control sequence name attached to Chosen,
% the second argument is the name of the list from which something is chosen
\define[2]\RandomChoice{%
\setevalue{Chosen#1}{\ctxlua{%
local listsize = \letterhash #2 ;
local LName = #2 ;
tex.print(LName[math.random(1,listsize)])}}}
\dorecurse{10}{\RandomChoice{Function}{ListOfNames}%
Give an example of a function $\ChosenFunction : {\Bbb R} \longrightarrow {\Bbb
R}$ which has a derivative only at the origin, and such that
${\ChosenFunction}'(0) = 1$.\par \hairline\par}
\stoptext
%%%% end choose-element.tex
\starttext
\startluacode
local FunctionNames = { "G" , "W" }
local FunctionName = FunctionNames[1]
function document.SetFunctionNames(list)
FunctionNames = utilities.parsers.settings_to_array(list)
end
function document.GetFunctionName(new)
if new then
FunctionName = FunctionNames[math.random(1,#FunctionNames)]
end
context(FunctionName)
end
\stopluacode
\def\SetFunctionNames[#1]{\ctxlua{document.SetFunctionNames("#1")}}
\def\NewFunctionName {\ctxlua{document.GetFunctionName(true)}}
\def\GetFunctionName {\ctxlua{document.GetFunctionName()}}
\SetFunctionNames[a,b,c,d]
\dorecurse{10}{
Give an example of a function
$\NewFunctionName : {\Bbb R} \longrightarrow {\Bbb R}$
which has a derivative only at the origin, and such that
$\GetFunctionName(0) = 1$.
\par \hairline\par
}
\stoptext
On 18 Apr 2015, at 19:23, Wolfgang Schuster <schuster.wolfg...@gmail.com> wrote:
Am 18.04.2015 um 18:55 schrieb Otared Kavian <ota...@gmail.com>:
Hi everyone,
In the example below I define a macro which chooses at random a name from a
list of names. But I wonder whether this can be done in a more clever way
without using a numerical macro created with math.random in Lua. The
shortcoming of the macro below is that before hand I must know the nomber of
elements in the list of names (for instance 5 in the example below), while it
may happen that I need to create as many as random names that there are
elements in the list, but sometimes I don’t know what is this number.
Thanks for any insight and help.
Best regards: OK
%%%% begin random-names.tex
\setuprandomize[2015] % set a seed
\starttext
\startluacode
Name = {'F', 'G', 'u', 'v', 'W'}
\stopluacode
\define[3]\RandomName{%
\setevalue{Named#1}{\ctxlua{tex.print(math.random(#2,#3))}}}
\define\RandomFunctionName{\ctxlua{tex.print(Name[\NamedFunctionNumber])}}
\dorecurse{10}{\RandomName{FunctionNumber}{1}{5}%
Give an example of a function $\RandomFunctionName : {\Bbb R} \longrightarrow
{\Bbb R}$ which has a derivative only at the origin, and such that
$\RandomFunctionName(0) = 1$.\par \hairline\par}
\stoptext
%%%% begin random-names.tex
You can access the size of your Name table with #Name but have to replace #
with \letterhash when you use it in a TeX command because # is already taken
for the TeX arguments.
\starttext
\startluacode
Name = {'F', 'G', 'u', 'v', 'W'}
\stopluacode
\define\RandomFunctionName
{\startlua
local listsize = \letterhash Name ;
local randomvalue = math.random(1,listsize) ;
context(Name[randomvalue])
\stoplua}
\dorecurse{10}{Give an example of a function $\RandomFunctionName : {\Bbb R}
\longrightarrow {\Bbb R}$ which has a derivative only at the origin, and such
that $\RandomFunctionName(0) = 1$.\par \hairline\par}
\stoptext
Wolfgang
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