Hi, I noticed an extra space in an enumeration when using \setcharacterkerning in the \headstyle parameter. The extra space appears before the first word "Sats", and in my case it is unwanted (In the example I want the word Sats to align with a), b), ...).
The space was not there a year ago, with the same code.
In the test file below (sorry for its length), the environment sats is
having the problem, while SATS does not. The only difference is in the
\headstyle parameter.
Am I missing something obvious?
/Mikael
PS I use the version of today, where the curious problems with sizes inside
square roots and fractions seem to be gone.
%%%%%%%%% Testfile starts here
\setupbodyfont[stixtwo,10bp]
\definemeasure[myitemwidth][26bp]
\definemeasure[myindent][12bp]
\setupindenting[yes,\measure{myindent}]
\definecharacterkerning[sats][factor=0.1]
\define[1]\vakuum{\hskip\measure{myindent}#1.}
\defineenumeration[sats][
text={Sats},
style={\em},
title=yes,
titlestyle=,
width=fit,
headstyle={\smallcaps\setcharacterkerning[sats]},
headcommand={\vakuum},
number=yes,
alternative=serried,
indenting={yes,\measure{myindent}},
]
\defineenumeration[SATS][sats][
headstyle=\smallcaps,%It is this setting that kills the space.
]
\defineitemgroup[delab]
\setupitemgroup[delab][each][a,intro,intext][
stopper=,
right=),
left={\hskip\measure{myindent}},
width=\measure{myitemwidth},
inbetween=,
before={\blank[none,samepage]},
after=,
style={\tf},
]
\starttext
\startTEXpage[offset=3bp]
\samplefile{ward}
\startsats[title={Räkneregler för gränsvärden}]
Antag att $c$ är ett tal, och att $a_k\to A$ och $b_k\to B$ då
$k\to+\infty$. Då gäller det, när $k\to+\infty$, att
\startdelab
\item $a_k+b_k\to A+B$,
\item $c\cdot a_k\to cA$,
\item $a_kb_k\to AB$,
\item $1/a_k\to 1/A$ (om $a_k\neq 0$ för alla $k$ och $A\neq 0$).
\stopdelab
\stopsats
\samplefile{ward}
\startSATS[title={Räkneregler för gränsvärden}]
Antag att $c$ är ett tal, och att $a_k\to A$ och $b_k\to B$ då
$k\to+\infty$. Då gäller det, när $k\to+\infty$, att
\startdelab
\item $a_k+b_k\to A+B$,
\item $c\cdot a_k\to cA$,
\item $a_kb_k\to AB$,
\item $1/a_k\to 1/A$ (om $a_k\neq 0$ för alla $k$ och $A\neq 0$).
\stopdelab
\stopSATS
\samplefile{ward}
\stopTEXpage
\stoptext
%%%%%%%%%%%
spaceprob.pdf
Description: Adobe PDF document
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