I might be able to, but I haven't explored that route yet.  I was not sure if I 
had hit an unintended error or not.
In particular I have a need for something similar to the modified version of 
pfdnacluster_master that Chris Wakelin created.
I will need the cluster to duplicate all packets to three different 
applications.  The first application will only need one ring, the second will 
need two rings, and the third will need ~12 rings.  The second and third 
applications will need traffic load-balanced (with flows preserved) among their 
rings.  I don't believe the modified version will handle distribution in this 
manner without requiring similar tweaking.

Thanks,
Jake G.



From: [email protected] 
[mailto:[email protected]] On Behalf Of Alfredo Cardigliano
Sent: Friday, April 05, 2013 11:50 AM
To: [email protected]
Subject: Re: [Ntop-misc] pfdnacluster listening to pfdnacluster

Hi Jake
this is not possible, what do you want to do in practice? I think you can 
achieve the same with less overhead playing with the distribution function.

Best Regards
Alfredo

On Apr 5, 2013, at 5:54 PM, "Gionet, Jake" 
<[email protected]<mailto:[email protected]>> wrote:


Is it possible to have one DNA cluster listen to another DNA cluster?
A simple example of what I'm trying to do (with error message) is:


root@ubuntu:~/PF_RING-5.5.3/userland/examples#<mailto:root@ubuntu:~/PF_RING-5.5.3/userland/examples#>
 ./pfdnacluster_master -a -i dna1 -c 1 -n 1 -d
root@ubuntu:~/PF_RING-5.5.3/userland/examples#<mailto:root@ubuntu:~/PF_RING-5.5.3/userland/examples#>
 ./pfdnacluster_master -a -i dnacluster:1 -c 2 -n 1
Capturing from dnacluster:1
Using PF_RING v.5.5.3
Error registering rx socket
root@ubuntu:~/PF_RING-5.5.3/userland/examples#<mailto:root@ubuntu:~/PF_RING-5.5.3/userland/examples#>



It appears that dna_cluster_register_ring does not accept a ring that was 
created to another DNA cluster as a parameter.  Is this accurate?
If this is the case, is it possible to fix this and/or get around this 
limitation somehow?

Thanks,
Jake G.

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