Noticed this a while ago and worked around it (by doing the
multiplication manually)
Problem is when I multiple a vector by a matrix, it seems to be ignoring
the translation part:
m = nuke.math.Matrix4()
vals = [
1, 0, 0, 5,
0, 1, 0, 0,
0, 0, 1, 0,
0, 0, 0, 1
]
for i, v in enumerate(vals):
m[i] = v
print m * nuke.math.Vector4(0, 0, 0, 1)
I would expect this to return a value of 5 for x, because:
1*0 + 0*0 + 0*0 + 5*1 == 5
Instead it seems to ignore the last column in the matrix and returns (0,
0, 0, 1)
Is this correct? Seems like it could be a bug with the wrapping of the
nuke.math module (which... wouldn't be unheard of, thus the convoluted
method of initialising the matrix)
--
ben dickson
2D TD | [email protected]
rising sun pictures | www.rsp.com.au
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