From what I can see it's used to create a new set of unique items
(correct me if I'm wrong!)
for example:
listA = set(["a", "b", "c"])
listB = set(["b", "c", "d"])
listC = listA.union(listB)
print listC
prints:
# Result:
set(['a', 'c', 'b', 'd'])
see http://docs.python.org/library/stdtypes.html#set
Tom
On 27/04/2012 12:08, Howard Jones wrote:
Out of interest ...
what does 'union' do in this script
Howard
------------------------------------------------------------------------
*From:* Nathan Rusch <[email protected]>
*To:* [email protected]
*Sent:* Friday, 27 April 2012, 3:42
*Subject:* Re: [Nuke-python] Re: selecting a node from its name
Same function with one line cleaned up (sorry, itâEUR^(TM)s been a
long day...)
def recursiveFindReads(node=None, group=nuke.root(), reads=None):
if reads is None:
reads = set()
if node is None:
node = nuke.selectedNode() # Let this error on purpose if
no node selected
for n in node.dependencies(nuke.INPUTS | nuke.HIDDEN_INPUTS):
cls = n.Class()
if cls == 'Read':
reads.add(n)
elif cls == 'Group':
reads =
reads.union(recursiveFindReads(node=nuke.allNodes('Output',
group=n)[0], group=n, reads=reads))
else:
reads = reads.union(recursiveFindReads(node=n,
group=group, reads=reads))
return reads
If you really DO need to select them, just run this:
nukescripts.clear_selection_recursive()
[n.setSelected(True) for n in recursiveFindReads()]
-Nathan
*From:* invisfx <mailto:[email protected]>
*Sent:* Thursday, April 26, 2012 7:35 PM
*To:* [email protected]
<mailto:[email protected]>
*Subject:* [Nuke-python] Re: selecting a node from its name
what I meant by loop is
depNodes = selectedNode.dependencies()
only selects the immediate dependencies, not all the way up the
graph. So I have to re select those nodes and do it again.
or am I wrong?
------------------------------------------------------------------------
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