Out of curiosity I checked on what matlab does. 
It does explicity set the last value to 'stop' to avoid the roundoff issue.
In numpy terms, it does something like
   y = r_[start+r_[0:num-1]*(stop-start)/(num-1.0 ),  stop]

But for numpy it's probably more efficient to just do the 'y[-1] = stop' like you say.


--bb

On 8/22/06, Alan G Isaac < [EMAIL PROTECTED]> wrote:
The definition of linspace is:
def linspace(start, stop, num=50, endpoint=True, retstep=False):
    """Return evenly spaced numbers.

    Return 'num' evenly spaced samples from 'start' to 'stop'.  If
    'endpoint' is True, the last sample is 'stop'. If 'retstep' is
    True then return the step value used.
    """
    num = int(num)
    if num <= 0:
        return array([], float)
    if endpoint:
        if num == 1:
            return array([float(start)])
        step = (stop-start)/float((num-1))
    else:
        step = (stop-start)/float(num)
    y = _nx.arange(0, num) * step + start
    if retstep:
        return y, step
    else:
        return y

The simplest way to achieve this goal is to add right after
the assignment to y two new lines:
   if endpoint:
       y[-1] = float(stop)

Cheers,
Alan Isaac

PS I'll take this opportunity to state again my opinion that
in the denerate case num=1 that if endpoint=True then
linspace should return stop rather than start.  (Otherwise
endpoint is ignored. But I do not expect anyone to agree.)



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