On 8/29/06, Tim Hochberg <[EMAIL PROTECTED]> wrote: > Keith Goodman wrote: > > I have a very long list that contains many repeated elements. The > > elements of the list can be either all numbers, or all strings, or all > > dates [datetime.date]. > > > > I want to convert the list into a matrix where each unique element of > > the list is assigned a consecutive integer starting from zero. > > > If what you want is that the first unique element get's zero, the second > one, I don't think the code below will work in general since the dict > does not preserve order. You might want to look at the results for the > character case to see what I mean. If you're looking for something else, > you'll need to elaborate a bit. Since list2index doesn't return > anything, it's not entirely clear what the answer consists of. Just idx? > Idx plus uL?
The output I wanted (in my mind, but unfortunately not in my previous email) is idx and uL where uL[0] corresponds to the zeros in idx, uL[1] corresponds to the ones in idx. etc. I'd also like the uL's to be ordered (now I see that characters and dates aren't ordered, ooops, thanks for telling me about that). Or optionally ordered by a second list input which if present would be used instead of the unique values of L. Thank you all for the huge improvements to my code. I'll learn a lot studying all of them. ------------------------------------------------------------------------- Using Tomcat but need to do more? Need to support web services, security? Get stuff done quickly with pre-integrated technology to make your job easier Download IBM WebSphere Application Server v.1.0.1 based on Apache Geronimo http://sel.as-us.falkag.net/sel?cmd=lnk&kid=120709&bid=263057&dat=121642 _______________________________________________ Numpy-discussion mailing list Numpy-discussion@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/numpy-discussion
