Hi, Vectorize is a very handy function, but it has at least one pitfall:
def f(x): if 1.3<x<2.5: return sqrt(x) else: return 0 Now vectorize(f)(2)=1.41421356237 but vectorize(f)(array([1,2]))=array([0,1]). The problem is that, when given an array as input, vectorize feeds in the first element, looks at the return type, and returns an array of that type - and I didn't put a "." after the zero. This should perhaps be in the docstring of vectorize, since I can't see any way to work around it, but it can easily lead to difficult-to-find bugs. It may seem like an artificial example, but it came up with a function I was working on. But it's confusing behaviour. vectorize appears to support an "otypes" argument, but it doesn't take standard numpy type objects, and it doesn't do anything obvious. Perhaps I should file a ticket, but first I'd like to understand the correct behaviour... A. M. Archibald ------------------------------------------------------------------------- Using Tomcat but need to do more? Need to support web services, security? Get stuff done quickly with pre-integrated technology to make your job easier Download IBM WebSphere Application Server v.1.0.1 based on Apache Geronimo http://sel.as-us.falkag.net/sel?cmd=lnk&kid=120709&bid=263057&dat=121642 _______________________________________________ Numpy-discussion mailing list Numpy-discussion@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/numpy-discussion