Even knowing that, it's still confusing that round(np.float64(0.0)) isn't the same as round(0.0). The reason is a Python 2 / Python 3 thing: in Python 2, round returns a float, while on Python 3, it returns an integer – but numpy still uses the python 2 behavior everywhere.
I'm not sure if it's possible or worthwhile to change this. If we'd changed it when we first added python 3 support then it would have been easy (and obviously a good idea), but at this point it might be tricky? -n On Thu, Mar 22, 2018 at 12:32 PM, Nathan Goldbaum <nathan12...@gmail.com> wrote: > numpy.float is an alias to the python float builtin. > > https://github.com/numpy/numpy/issues/3998 > > > On Thu, Mar 22, 2018 at 2:26 PM Olivier <oc-spa...@laposte.net> wrote: >> >> Hello, >> >> >> Is it normal, expected and desired that : >> >> >> round(numpy.float64(0.0)) is a numpy.float64 >> >> >> while >> >> round(numpy.float(0.0)) is an integer? >> >> >> I find it disturbing and misleading. What do you think? Has it already >> been >> discussed somewhere else? >> >> >> Best regards, >> >> >> Olivier >> >> _______________________________________________ >> NumPy-Discussion mailing list >> NumPy-Discussion@python.org >> https://mail.python.org/mailman/listinfo/numpy-discussion > > > _______________________________________________ > NumPy-Discussion mailing list > NumPy-Discussion@python.org > https://mail.python.org/mailman/listinfo/numpy-discussion > -- Nathaniel J. Smith -- https://vorpus.org _______________________________________________ NumPy-Discussion mailing list NumPy-Discussion@python.org https://mail.python.org/mailman/listinfo/numpy-discussion