On Wed, Feb 13, 2019 at 1:35 PM Mauro Cavalcanti <mauro...@gmail.com> wrote:
> Dear ALL, > > In the process of porting an existing (but abandoned) package to the > latest version of Numpy, I stumbled upon a call to a 'numpy.nansqrt' > function, which seems not to exist. > > Here is the specific code: > > def normTrans(y): > denom = np.nansqrt(np.nansum(y**2)) > return y/denom > > As far as I could find, there is no such 'nansqrt' function in the current > version of Numpy, so I suspect that the above code has not been properly > tested. > > Am I right, or that function had existed in some past version of Numpy? > > Thanks in advance for any comments or suggestions. > > I don't recall any such function, but nansum will not result in any nans, so plain old sqrt should work. Chuck
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