Thanks for the quick explanation & answers. I was mostly puzzled by the absence 
of warning.
In C you would get an overflow warning in such a case, no ?


Nicolas

> On 3 Jul 2019, at 20:01, Charles R Harris <charlesr.har...@gmail.com> wrote:
> 
> 
> 
> On Wed, Jul 3, 2019 at 11:39 AM Matthew Brett <matthew.br...@gmail.com> wrote:
> Hi,
> 
> On Wed, Jul 3, 2019 at 9:08 AM Charles R Harris
> <charlesr.har...@gmail.com> wrote:
> >
> >
> >
> > On Wed, Jul 3, 2019 at 9:08 AM Hameer Abbasi <einstein.edi...@gmail.com> 
> > wrote:
> >>
> >> Hi,
> >>
> >> It turns out you're running into a bit-error. In general, the two's 
> >> complement of -2 ** (n-1) with the bit-length being limited to n bits is 
> >> itself... No way around that. And integers don't set hardware exceptions 
> >> so checking for errors like these is hard as well.
> >>
> >> TL;DR: It's an error with how the integer is stored in memory and how 
> >> you're running out of space.
> >>
> >> Regards,
> >> Hameer Abbasi
> >
> >
> > More like the eight bit twos complement of -128 is -128, bytes cannot 
> > represent 128. Matlab used to (still does?) solve this problem by returning 
> > 127 instead :) Basically, the data needs more precision. Returning an 
> > unsigned type would lead to it's own problems with unexpected promotions 
> > when the result was used. We could, I suppose, raise a warning, although 
> > that might be considered noisy. If you use `absolute` instead, you can 
> > specify the dtype.
> 
> I still think this is a major wart in numpy's abs.
> 
> I'd really like to add a new function, `uabs` which would return an
> unsigned int for integer inputs.  I'm happy to do a pull request if
> that also seems sensible to y'all,
> 
> 
> Seems reasonable, it would provide something for discussion. Note that the 
> current abs is in the slot provided by Python numeric types. The main problem 
> is that as soon as the unsigned result is combined with a signed type it will 
> get promoted. Which would not be much of a problem except int64 -> double.
> 
> Chuck
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