Hi Will, To force an iteration to run along certain axes, I believe you should be using `op_axes`. Your diagnosis is correct that `external_loop` is trying to help you be more optimal, since it's purpose is exactly that: optimization.
Unfortunately, if you use `op_axes` you'll run into https://github.com/numpy/numpy/issues/9808. Eric On Tue, 19 May 2020 at 00:42, William Ayd <william....@icloud.com> wrote: > I am trying to use the nditer to traverse each column of a 2D array, > returning the column as a 1D array. Consulting the docs, I found this > example which works perfectly fine: > > In [*65*]: a = np.arange(6).reshape(2,3) > > > > In [*66*]: *for* x *in* np.nditer(a, flags=['external_loop'], order='F'): > ...: print(x, end=' ') > ...: > > > [0 3] [1 4] [2 5] > > When changing the shape of the input array to (1, 3) however, this doesn’t > yield what I am hoping for any more (essentially [0], [1] [2]): > > In [*68*]: *for* x *in* np.nditer(a, flags=['external_loop'], order='F'): > ...: print(x, end=' ') > ...: > > > [0 1 2] > > I suspect this may have to do with the fact that the (1, 3) array is both > C and F contiguous, and it is trying to return as large of a 1D > F-contiguous array as it can. However, I didn’t see any way to really force > it to go by columns. My best guess was the *itershape* argument though I > couldn’t figure out how to get that to work and didn’t see much in the > documentation. > > Thanks in advance for the help! > > - Will > > > > _______________________________________________ > NumPy-Discussion mailing list > NumPy-Discussion@python.org > https://mail.python.org/mailman/listinfo/numpy-discussion >
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