On 2/21/07, Charles R Harris <[EMAIL PROTECTED]> wrote:
On 2/21/07, Timothy Hochberg <[EMAIL PROTECTED]> wrote:
>
>
>
> On 2/21/07, Charles R Harris < [EMAIL PROTECTED]> wrote:
> >
> >
> >
> > On 2/21/07, Robert Kern < [EMAIL PROTECTED]> wrote:
> > >
> > > Christopher Barker wrote:
> > > > Robert Kern wrote:
> > > >> Christopher Barker wrote:
> > > >>> I wonder if there are any C math libs that do a better job than
> > > you'd
> > > >>> expect from standard FP? (short of unlimited precision ones)
> > > >> With respect to π and the zeros of sin() and cos()? Not really.
> >
> >
> > <snip>
> >
> > Well, you can always use long double if it is implemented on your
> > > platform. You
> > > will have to construct a value for π yourself, though. I'm afraid
> > > that we don't
> > > really make that easy.
> > >
> > > --
> >
> >
> > pi = 3. 1415926535 8979323846 2643383279 5028841971 6939937510
> > 5820974944 5923078164 0628620899 8628034825 3421170679 8214808651 *...
> >
> > *
> > I dont know what that looks like when converted to long double.
> > Lessee,
> >
> > In [1]: import numpy
> >
> > In [2]: pi = numpy.float128(3.1415926535897932384626433832795028841971
> > )
> >
>
> I think this is where you go wrong. Your string of digits is first a
> python float and *then* is converted to a long double. In the intermediate
> stage it gets truncated and you don't get the precision back.
>
True. But there is missing functionality here.
In [4]: pi = numpy.float128('3.1415926535897932384626433832795028841971')
---------------------------------------------------------------------------
exceptions.TypeError Traceback (most
recent call last)
/home/charris/workspace/microsat/daemon/<ipython console>
TypeError: a float is required
It's somewhat pointless to have a data type that you can't properly
initialize. I think the string value should work, it works for python types.
OTOH, the old way does give extended precision for pi
In [8]: numpy.arctan2(numpy.float128(1), numpy.float128(1))*4
Out[8]: 3.14159265358979323851
Chuck
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