David Koch wrote: > Hi, > > so one thing I came across now is the following, very simple: > > Matlab: > A = [] > while .... > A = [A some_scalar_value] > end > > > In Python, I tried: > > A = empty((0,0)) > while .... > A = concatenate((A, array([someScalarValue])), 1) > end > > which returns an error since the shape of the empty A does not match the > vector I want to concatenate with. Any way to get around this without > having > to use some obscure "if exist A" clause. I am still stuck in my Matlab ways > - hoping to get rid of them though.
a = empty( (0,) ) ... I would bet that using a regular Python list would be faster in this case than growing the numpy array. a = [] while ... a.append( scalar ) a = array( a ) r. _______________________________________________ Numpy-discussion mailing list Numpy-discussion@scipy.org http://projects.scipy.org/mailman/listinfo/numpy-discussion
