It's not a question of tuple, you made a tuple, but in each element, you put the same array, so this behaviour is to be expected.
Matthieu 2007/11/15, George Nurser <[EMAIL PROTECTED]>: > > I tried the (as I thought) nice compact form > In [60]: a,b = (zeros((2,)),)*2 > > But... > > In [61]: b[0] = 2 > > In [62]: a > Out[62]: array([ 2., 0.]) > > a and b are the _same_ array.... > > But > In [68]: a,b = (zeros((2,)),zeros((2,))) > > In [69]: b[0] = 2 > > In [70]: a > Out[70]: array([ 0., 0.]) > > is OK. a & b are independent in this case. > > I'm puzzled by this behaviour, I suspect because of my ignorance of > how tuples work. > > It looks to me like > a,b = (zeros((2,)),)*2 > is equivalent to > x= zeros((2,)) > a,b=(x,)*2 > > If this is indeed a feature rather than a bug, is there an alternative > compact way to allocate many arrays? > > > Regards, George. > _______________________________________________ > Numpy-discussion mailing list > Numpy-discussion@scipy.org > http://projects.scipy.org/mailman/listinfo/numpy-discussion > -- French PhD student Website : http://miles.developpez.com/ Blogs : http://matt.eifelle.com and http://blog.developpez.com/?blog=92 LinkedIn : http://www.linkedin.com/in/matthieubrucher
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