> There is one more important case, which is aligning just the beginning > of the array.
Indeed -- thanks! The following should take care of that case (it's all fluff around calling aligned_empty() with a dim_alignments tuple of all 1's, and the array_alignment parameter as required): def aligned_start_empty(shape, dtype, alignment, order='C'): '''Return an array with the first element aligned to a byte that is evenly-divisible by the specified alignment.''' order = order.upper() if order not in ('C', 'F'): raise ValueError("Order must be 'C' or 'F'.") dim_alignments = [1 for dim in shape] if order == 'F': shape = shape[::-1] return aligned_empty(shape, dtype, dim_alignments, alignment).T else: return aligned_empty(shape, dtype, dim_alignments, alignment) Zach _______________________________________________ Numpy-discussion mailing list Numpy-discussion@scipy.org http://projects.scipy.org/mailman/listinfo/numpy-discussion