On Thu, May 22, 2008 at 7:19 PM, Tom Waite <[EMAIL PROTECTED]> wrote:
> I have a question on filling a lower triangular matrix using numpy. This
> is essentially having two loops and the inner loop upper limit is the
> outer loop current index. In the inner loop I have a vector being
> multiplied by a constant set in the outer loop. For a matrix N*N in size,
> the C the code is:
>
> for(i = 0; i < N; ++i){
> for(j = 0; j < i; ++j){
> Matrix[i*N + j] = V1[i] * V2[j];
> }
> }
>
>
You can use numpy.outer(V1,V2) and just ignore everything on and above the
diagonal.
In [1]: x = arange(3)
In [2]: y = arange(3,6)
In [3]: outer(x,y)
Out[3]:
array([[ 0, 0, 0],
[ 3, 4, 5],
[ 6, 8, 10]])
You can mask the upper part if you want:
In [16]: outer(x,y)*fromfunction(lambda i,j: i>j, (3,3))
Out[16]:
array([[0, 0, 0],
[3, 0, 0],
[6, 8, 0]])
Or you could use fromfunction directly.
Chuck
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