Hi Darren, If I remember correctly, the thinking under the current behavior is that it preserves similarity of results with histogramdd, where the histogram is oriented in the numpy order (columns, rows). I thought that making histogram2d(x,y) return something different than histogramdd([x,y]) was probably worst than satisfying the cartesian convention.
Regards, David 2008/5/29 Darren Dale <[EMAIL PROTECTED]>: > I have a question about histogram2d. Say I do something like: > > import numpy > from numpy import random > import pylab > > x=random.rand(1000)-0.5 > y=random.rand(1000)*10-5 > > xbins=numpy.linspace(-10,10,100) > ybins=numpy.linspace(-10,10,100) > h,x,y=numpy.histogram2d(x,y,bins=[xbins,ybins]) > > pylab.imshow(h,interpolation='nearest') > pylab.show() > > The output is attached. I think I would have expected the transpose of what > numpy histogram2d returned, so the tight x distribution appears along the x > axis in the image. Maybe I am thinking about this incorrectly, or there is > a > convention I am unfamiliar with. If the behavior is correct, could the > docstring include a comment explaining the orientation of the histogram > array? > > Thanks, > Darren > > -- > Darren S. Dale, Ph.D. > Staff Scientist > Cornell High Energy Synchrotron Source > Cornell University > 275 Wilson Lab > Rt. 366 & Pine Tree Road > Ithaca, NY 14853 > > [EMAIL PROTECTED] > office: (607) 255-3819 > fax: (607) 255-9001 > http://www.chess.cornell.edu > > _______________________________________________ > Numpy-discussion mailing list > Numpy-discussion@scipy.org > http://projects.scipy.org/mailman/listinfo/numpy-discussion > >
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