On Wed, Jun 4, 2008 at 9:50 PM, Dan Yamins <[EMAIL PROTECTED]> wrote: >> >> In [3]: numpy.dtype(numpy.uintp).itemsize >> Out[3]: 4 >> >> which is the size in bytes of the integer needed to hold a pointer. The >> output above is for 32 bit python/numpy. >> > > Check, the answer is 4, as you got for the 32-bit. What would the answer > be on a 64-bit architecture? Why is this diagnostic?
It would be 8 on a 64-bit architecture (with a 64-bit binary): 8 bytes = 64 bits, 4 bytes = 32 bits. -- Nathan Bell [EMAIL PROTECTED] http://graphics.cs.uiuc.edu/~wnbell/ _______________________________________________ Numpy-discussion mailing list Numpy-discussion@scipy.org http://projects.scipy.org/mailman/listinfo/numpy-discussion
